(x^2+4x-5)(x-5)=

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Solution for (x^2+4x-5)(x-5)= equation: 


Simplifying
(x2 + 4x + -5)(x + -5) = 0

Reorder the terms:
(-5 + 4x + x2)(x + -5) = 0

Reorder the terms:
(-5 + 4x + x2)(-5 + x) = 0

Multiply (-5 + 4x + x2) * (-5 + x)
(-5(-5 + x) + 4x * (-5 + x) + x2(-5 + x)) = 0
((-5 * -5 + x * -5) + 4x * (-5 + x) + x2(-5 + x)) = 0
((25 + -5x) + 4x * (-5 + x) + x2(-5 + x)) = 0
(25 + -5x + (-5 * 4x + x * 4x) + x2(-5 + x)) = 0
(25 + -5x + (-20x + 4x2) + x2(-5 + x)) = 0
(25 + -5x + -20x + 4x2 + (-5 * x2 + x * x2)) = 0
(25 + -5x + -20x + 4x2 + (-5x2 + x3)) = 0

Combine like terms: -5x + -20x = -25x
(25 + -25x + 4x2 + -5x2 + x3) = 0

Combine like terms: 4x2 + -5x2 = -1x2
(25 + -25x + -1x2 + x3) = 0

Solving
25 + -25x + -1x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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